我就废话不多说了，大家还是直接看代码吧~
example
>>> import re
>>> subject = '080045000106309140003F2F7D100A0A3C0A0A0A3D0A00000800450000EE000000003F06CCF0C0A8C864C0A8646400000000000000000000000050000000F7410000'
>>> result = re.sub(r"(?<=\w)(?=(?:\w\w)+$)", " ", subject)
>>> result
'08 00 45 00 01 06 30 91 40 00 3F 2F 7D 10 0A 0A 3C 0A 0A 0A 3D 0A 00 00 08 00 45 00 00 EE 00 00 00 00 3F 06 CC F0 C0 A8 C8 64 C0 A8 64 64 00 00 00 00 00 00 00 00 00 00 00 00 50 00 00 00 F7 41 00 00'补充：python 字符串输出时 使用空格隔开
使用python 中的join函数， 即可实现
example
In [77]: test = "12344345345"
In [78]: test
Out[78]: '12344345345'
In [79]: result = " ".join(test)
In [80]: result
Out[80]: '1 2 3 4 4 3 4 5 3 4 5'
以上为个人经验，希望能给大家一个参考，也希望大家多多支持编程网。如有错误或未考虑完全的地方，望不吝赐教。
