Windows后台运行python程序

import win32serviceutil
import win32service
import win32event
import time
class SmallestPythonService(win32serviceutil.ServiceFramework):
    _svc_name_ = "SmallestPythonService"
    _svc_display_name_ = "The smallest possible Python Service"
    def __init__(self, args):
        win32serviceutil.ServiceFramework.__init__(self, args)
        # Create an event which we will use to wait on.
        # The "service stop" request will set this event.
        self.hWaitStop = win32event.CreateEvent(None, 0, 0, None)

    def SvcStop(self):
        # Before we do anything, tell the SCM we are starting the stop process.
        self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
        # And set my event.
        win32event.SetEvent(self.hWaitStop)

    def SvcDoRun(self):
        #你需要运行的代码#
        while True:
            f= open('c:/a.log','a')
            f.write('asdf\n')
            f.close()
            time.sleep(5)
        win32event.WaitForSingleObject(self.hWaitStop, win32event.INFINITE)

if __name__=='__main__':
    win32serviceutil.HandleCommandLine(SmallestPythonService) 

启动的方法就是直接在cmd下，脚本名.py install ，然后去windows 的服务下就可以看到The smallest possible Python Service 这个服务，你可以启动，停止，还可以设置成开机自动启动。

有个需要注意的地方：

该脚本名不能为中文！！否则在启动服务时会出现“ Windows 不能 在本地计算机 启动 The smallest possible Python Service .....“的错误信息