本文主要介绍了SQLServer RANK() 排名函数的使用,具体如下:
-- 例子表数据
SELECT * FROM test;
-- 统计分数
SELECT name,SUM(achievement) achievement FROM test GROUP BY name;
-- 按统计分数做排行
SELECT RANK() OVER( ORDER BY SUM(achievement) desc) 排行,name,SUM(achievement) achievement FROM test GROUP BY name;
求助问答存储过程使用:
USE [DB]
GO
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
-- =============================================
-- Author: _Hey_Jude
-- Create date: 2021-01-26
-- Description: 获取今日发表帮助/回复的新用户
-- =============================================
CREATE PROCEDURE [dbo].[sp_TodayJoinUser]
@tableLevel int,
@date varchar(30)
AS
Declare @Sql nvarchar(max)
declare @minTabId int
declare @maxTabId int
declare @maxf_id int
declare @helpTableName nvarchar(max)
declare @tableCount int
BEGIN
--最小f_id所在表
set @minTabId=0
set @tableCount=@minTabId
--最大f_id所在表
set @maxf_id=(select MAX(F_ID) from [Table] where F_IsDelete=0)
set @maxTabId=@maxf_id/@tablelevel
set @helpTableName='SELECT UserID, Max([F_DateTime]) AS dt FROM [Table] GROUP BY UserID'
while @tableCount<=@maxTabId
begin
print @tableCount
set @helpTableName += ' UNION SELECT UserID, Max([DateTime]) as dt FROM SubTable'+cast(@tableCount as nvarchar(10))+' GROUP BY UserID '
set @tableCount=@tableCount+1
end
set @Sql='SELECT [nikename] FROM (
SELECT UserID, RANK() OVER(PARTITION BY UserID ORDER BY dt) AS Num,dt FROM ( '+@helpTableName+' ) AS T ) AS NewT
LEFT JOIN [UserTable] A WITH(NOLOCK) ON NewT.UserID = A.UserId WHERE Num = 1 AND dt > '''+@date+''''
Exec sp_executesql @Sql
END
GO
partition的意思是对数据进行分区,sql语句如下
SELECT* FROM (
SELECT
ROW_NUMBER() over(partition by [姓名] order by [打卡时间] desc) as rowNum,
[姓名],
[打卡时间]
FROM [dbo].[打卡记录表]
) temp
WHERE temp.rowNum = 1
通过 partition by [姓名] order by [打卡时间] desc,这句就可以做到,让数据按照姓名分组,并且在每组内部按照时间进行排序
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