本篇内容介绍了“mysql insert导致死锁的案例介绍”的有关知识，在实际案例的操作过程中，不少人都会遇到这样的困境，接下来就让小编带领大家学习一下如何处理这些情况吧！希望大家仔细阅读，能够学有所成！
两个insert语句发生死锁的案例。
一. 准备数据
CREATE TABLE `t1` (
`a` int(11) NOT NULL,
PRIMARY KEY (`a`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4;
insert into t1 values(1);
mysql> insert into t1 values(1);
Query OK, 1 row affected (0.20 sec)
mysql> select * from t1;
+---+
| a |
+---+
| 1 |
+---+
1 row in set (0.00 sec)二. 发起如下事务
会话1 | 会话2 | 会话3 |
begin; delete from t1 where a=1; | ||
begin; insert into t1 select 1; | ||
begin; insert into t1 select 1; | ||
Commit | ||
ERROR 1213 (40001): Deadlock found when trying to get lock; try restarting transaction |
简单理解下，删除数据的会话持有X锁，导致两条insert语句需要等待，这没问题，
但是为什么删除提交后，两个竞争关系出现了死锁。
show engine innodb status部分结果：
------------------------
LATEST DETECTED DEADLOCK
------------------------
2020-05-17 13:50:24 0x7f660c3f0700
*** (1) TRANSACTION:
TRANSACTION 4377, ACTIVE 13 sec inserting
mysql tables in use 1, locked 1
LOCK WAIT 3 lock struct(s), heap size 1136, 2 row lock(s)
MySQL thread id 3, OS thread handle 140076399294208, query id 59 localhost root executing
insert into t1 select 1
*** (1) WAITING FOR THIS LOCK TO BE GRANTED:
RECORD LOCKS space id 99 page no 3 n bits 72 index PRIMARY of table `ming`.`t1` trx id 4377 lock_mode X locks rec but not gap waiting
Record lock, heap no 2 PHYSICAL RECORD: n_fields 3; compact format; info bits 32
0: len 4; hex 80000001; asc ;;
1: len 6; hex 000000001114; asc ;;
2: len 7; hex 3400000144129f; asc 4 D ;;
*** (2) TRANSACTION:
TRANSACTION 4378, ACTIVE 10 sec inserting, thread declared inside InnoDB 1
mysql tables in use 1, locked 1
3 lock struct(s), heap size 1136, 2 row lock(s)
MySQL thread id 4, OS thread handle 140076268848896, query id 61 localhost root executing
insert into t1 select 1
*** (2) HOLDS THE LOCK(S):
RECORD LOCKS space id 99 page no 3 n bits 72 index PRIMARY of table `ming`.`t1` trx id 4378 lock mode S
Record lock, heap no 2 PHYSICAL RECORD: n_fields 3; compact format; info bits 32
0: len 4; hex 80000001; asc ;;
1: len 6; hex 000000001114; asc ;;
2: len 7; hex 3400000144129f; asc 4 D ;;
*** (2) WAITING FOR THIS LOCK TO BE GRANTED:
RECORD LOCKS space id 99 page no 3 n bits 72 index PRIMARY of table `ming`.`t1` trx id 4378 lock_mode X locks rec but not gap waiting
Record lock, heap no 2 PHYSICAL RECORD: n_fields 3; compact format; info bits 32
0: len 4; hex 80000001; asc ;;
1: len 6; hex 000000001114; asc ;;
2: len 7; hex 3400000144129f; asc 4 D ;;
*** WE ROLL BACK TRANSACTION (2)可以看到会话2正在等待一个X行锁，会话3也在等待X行锁，但是同时持有一个S锁。
这个S锁是怎么来的呢？
当进行唯一性冲突检测时，需要先加一个 S 锁。
那么整个过程就是如下所示
会话1 | 会话2 | 会话3 |
begin; delete from t1 where a=1; 持有a=1就的X行锁 | ||
begin; insert into t1 select 1; 为了判断唯一性，请求a=1的next-key lock S锁被阻塞，等待 | ||
begin; insert into t1 select 1; 为了判断唯一性，请求a=1的next-key lock S锁被阻塞，等待 | ||
Commit 释放a=1上的锁 | ||
拿到a=1的next-key lock S锁，继续尝试拿a=1的X 行锁，但是被会话3的S锁阻塞 | 拿到a=1的next-key lock S锁，继续尝试拿a=1的X 行锁，尝试拿到a=1的X 行锁，但是被会话2的S锁阻塞。 触发死锁 ERROR 1213 (40001): Deadlock found when trying to get lock; try restarting transaction |
“mysql insert导致死锁的案例介绍”的内容就介绍到这里了，感谢大家的阅读。如果想了解更多行业相关的知识可以关注亿速云网站，小编将为大家输出更多高质量的实用文章！
