本文小编为大家详细介绍“Python如何实现带图形界面的炸金花游戏”，内容详细，步骤清晰，细节处理妥当，希望这篇“Python如何实现带图形界面的炸金花游戏”文章能帮助大家解决疑惑，下面跟着小编的思路慢慢深入，一起来学习新知识吧。
炸金花
题目很简单：就是自己写一个程序，实现诈金花游戏的发牌、判断输赢。
规则：
一付扑克牌，去掉大小王，每个玩家发3张牌，最后比大小，看谁赢。
牌型：
豹子：三张一样的牌，如3张6.
顺金：又称同花顺，即3张同样花色的顺子， 如红桃 5、6、7
顺子：又称拖拉机，花色不同，但是顺子，如红桃5、方片6、黑桃7，组成的顺子
对子：2张牌一样
单张：单张最大的是A
版型大小顺序： 豹子>顺金>顺子>对子>单张
从网上百科到的诈金花各种牌型的出现概率，一起放进代码中增加一点趣味小知识。你可能不知道豹子出现的概率比同花顺大，实际打牌时同花顺反而比豹子小；顺子出现的概率比金花小，实际打牌时顺子反而比金花小；最大牌为5、6、7的单张牌型出现的概率都要比金花和顺子小，所以有的地方额外规定同一局中拿到“235”三张牌要比同局的豹子大。
回到正题，直接上代码，主要2个函数：一个计分、一个比大小
from random import shuffle as DealCards Players = 5 #人数pkPacks = 1 #扑克副数W = "单张","对子","顺子","金花","顺金","豹子"X = 74.38, 16.94, 3.26, 4.96, 0.22, 0.24 #出现概率Y = 0.54, 1.36, 2.44, 3.8, 5.43, 7.33, 9.5, 11.95, 14.66, 17.38 #单张概率V = *(str(i) for i in range(2,10)),*'TJQKA' #T代表10F = '♠', '♥', '♣', '♦'P = [f+v for f in F for v in V]*pkPacks def Scores(pokers): f,p = [],[] for poker in pokers: f.append(F.index(poker[0])+1) p.append(V.index(poker[1])+2) t = sorted(p) if len(set(t))==1: return 500_0000+t[0] #豹子 elif len(set(t))==2: #对子 if t[0]==t[1]: #对子一样大比较剩下的单张 return (100+t[1])*10000+t[2] else: return (100+t[1])*10000+t[0] else: if t[0]+1==t[1]==t[2]-1: if len(set(f))==1: return 400_0000+t[2] #顺金(同花顺) else: return 200_0000+t[2] #顺子 else: if len(set(f))==1: return ((300+t[2])*100+t[1])*100+t[0] #金花 else: return (t[2]*100+t[1])*100+t[0] #单张 def WhoWins(P): Pokers,Winner = [],[] for i in range(0,3*Players,3): Pokers.append(P[i:i+3]) for i,p in enumerate(Pokers,1): win = Scores(p) idx = win//100_0000 print(f"Player{i}: {*p,} - {W[idx]}") Winner.append(win) win = max(Winner) #没有判断“一样大”，如是则谁在前谁为大 idx = Winner.index(win) big = win//10000 win = big//100 per = X[win] if win else Y[big-5] pok = W[win] if win else '单'+V[big-2] print(f"【Player{idx+1} win!】--> {*Pokers[idx],} {pok}({per}%)\n") return P[3*Players:] #去掉每一局已发的牌 if __name__ == '__main__': DealCards(P) #以随机洗牌来模拟发牌 #Players = int(input('请输入参加的人数？')) PlayersMax = 52*pkPacks//3+1 if not 0<Players<PlayersMax: print(f'请注意：参与人数的范围 0 < Players < {PlayersMax} ！') else: count = 1 while len(P)>=3*Players: #所有牌(52*PokerPairs)发不够一局为止 print(f'第{count}局：') count += 1 P = WhoWins(P)运行结果：
第1局：
Player1: ('♥Q', '♣2', '♣8') - 单张
Player2: ('♦T', '♥7', '♠6') - 单张
Player3: ('♣4', '♠4', '♦2') - 对子
Player4: ('♠5', '♠9', '♥6') - 单张
Player5: ('♠7', '♠3', '♣5') - 单张
【Player3 win!】--> ('♣4', '♠4', '♦2') 对子(16.94%)
第2局：
Player1: ('♥2', '♥8', '♦4') - 单张
Player2: ('♦9', '♦3', '♥A') - 单张
Player3: ('♠J', '♣A', '♦K') - 单张
Player4: ('♠8', '♥9', '♥T') - 顺子
Player5: ('♣7', '♣9', '♣T') - 金花
【Player5 win!】--> ('♣7', '♣9', '♣T') 金花(4.96%)
第3局：
Player1: ('♦7', '♦J', '♠2') - 单张
Player2: ('♥J', '♦A', '♥K') - 单张
Player3: ('♥4', '♥5', '♦6') - 顺子
Player4: ('♣Q', '♣J', '♠T') - 顺子
Player5: ('♣K', '♦8', '♦5') - 单张
【Player4 win!】--> ('♣Q', '♣J', '♠T') 顺子(3.26%)
扩展
学习要举一反三，做完题目想到把这个程序的界面图形化。无非就是把牌型对应列表下标从下图中索引取出相应的图片来对应到Image控件上；想要输出的文字对应到text控件上；再整2个button控件绑定对应的事件动作。(代码中有第3个button是我测试用的)
PokersV1.py 完整源代码：
import tkinter as tkfrom PIL import Image,ImageTkfrom time import sleepfrom random import shuffle as DealCards Players = 4 #人数pkPacks = 1 #扑克副数isReady = True W = "单张","对子","顺子","金花","顺金","豹子"X = 74.38, 16.94, 3.26, 4.96, 0.22, 0.24 #出现概率Y = 0.54, 1.36, 2.44, 3.8, 5.43, 7.33, 9.5, 11.95, 14.66, 17.38 #单张概率V = *(str(i) for i in range(2,10)),*'TJQKA' #T代表10F = '♠', '♥', '♣', '♦' def loadCards(): infile = Image.open("pokers.png") Images = [] for j in range(4): image = [] for i in range(15): box = infile.crop((i*100,j*150,i*100+100,j*150+150)) img = ImageTk.PhotoImage(image=box) image.append(img) Images.append(image) infile.close() return Images def dealCards(): global cv,cards,isReady,P,Pokers if not isReady: return cv.itemconfig(txt1, text="") cv.itemconfig(txt2, text="") if len(Pokers): for j in range(3): for i in range(4): cv.itemconfig(cards[i][j], image=Cards[0][0]) cv.update() sleep(0.5) for j in range(3): for i in range(4): cv.itemconfig(cards[i][j], image=Cards[1][0]) cv.update() sleep(0.3) if len(P)==0 or len(P)<12: P = [f+v for f in F for v in V]*pkPacks DealCards(P) isReady = False def playCards(): global cv,isReady,P,Pokers,cards,Cards if isReady: return P = WhoWins(P) for i,pok in enumerate(Pokers): for j,p in enumerate(pok): x = F.index(p[0]) y = V.index(p[1]) #print(x,y,'-',i,j) cv.itemconfig(cards[i][j], image=Cards[x][y+2]) cv.update() isReady = True def Scores(pokers): f,p = [],[] for poker in pokers: f.append(F.index(poker[0])+1) p.append(V.index(poker[1])+2) t = sorted(p) if len(set(t))==1: return 500_0000+t[0] #豹子 elif len(set(t))==2: #对子 if t[0]==t[1]: #对子一样大比较剩下的单张 return (100+t[1])*10000+t[2] else: return (100+t[1])*10000+t[0] else: if t[0]+1==t[1]==t[2]-1: if len(set(f))==1: return 400_0000+t[2] #顺金(同花顺) else: return 200_0000+t[2] #顺子 else: if len(set(f))==1: return ((300+t[2])*100+t[1])*100+t[0] #金花 else: return (t[2]*100+t[1])*100+t[0] #单张 def WhoWins(P): global cv,txt1,txt2,Pokers Pokers,Winner = [],[] for i in range(0,3*Players,3): Pokers.append(P[i:i+3]) for i,p in enumerate(Pokers,1): win = Scores(p) idx = win//100_0000 print(f"Player{i}: {*p,} - {W[idx]}") Winner.append(win) win = max(Winner) #没有判断“一样大”，如是则谁在前谁为大 idx = Winner.index(win) big = win//10000 win = big//100 per = X[win] if win else Y[big-5] pok = W[win] if win else '单'+V[big-2] text1 = f"【Player{idx+1} win!】" text2 = f"{pok}{*Pokers[idx],} {per}%\n" print(text1,'--> ',text2) cv.itemconfig(txt1, text=text1) cv.itemconfig(txt2, text=text2) return P[3*Players:] #去掉每一局已发的牌 def test(): global Pokers print("测试：",Pokers) if __name__ == '__main__': root = tk.Tk() root.geometry('1024x768') root.title('诈金花') cv = tk.Canvas(root, width=1024, height=680, bg='darkgreen') cv.pack() Pokers = [] Cards = loadCards() cards = [[None]*3 for _ in range(4)] P = [f+v for f in F for v in V]*pkPacks DealCards(P) x1, x2, x3 = 400, 80, 730 y1, y2, y3 = 100, 550, 320 dx1,dx2,dy = 105, 105, 0 imgxy = [[(x1,y1),(x1+dx1,y1),(x1+2*dx1,y1)],[(x3,y3),(x3+dx2,y3+dy),(x3+2*dx2,y3+dy*2)], [(x1,y2),(x1+dx1,y2),(x1+2*dx1,y2)],[(x2,y3),(x2+dx2,y3+dy),(x2+2*dx2,y3+dy*2)]] for x,lst in enumerate(imgxy): for y,coord in enumerate(lst): cards[x][y] = cv.create_image(coord, image=Cards[0][0]) cv.create_rectangle(coord[0]-50,coord[1]-75,coord[0]+50,coord[1]+75) tx,ty = coord[0]-100,coord[1]+92 cv.create_text(tx,ty, text=f'Player{x+1}', fill='white') btn = [None]*3 btn[0] = tk.Button(root,text='发牌',command=dealCards,width=10) btn[1] = tk.Button(root,text='开牌',command=playCards,width=10) btn[2] = tk.Button(root,text='测试',command=test,width=10) for i in range(3): btn[i].place(y=710, x=350+i*110) txt1 = cv.create_text(510,300, fill='red', font=("宋体", 16)) txt2 = cv.create_text(510,360, fill='red', font=("宋体", 10)) root.mainloop()【编译程序】
Windows的Cmd窗口中执行如下命令，Mac系统自行百度：
pyinstaller -F exam.py --noconsole
注意：记得把上面的牌型图保存为Pokers.png和代码放一起运行。
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