今天就跟大家聊聊有关SQL中怎么判断给定日期值，可能很多人都不太了解，为了让大家更加了解，小编给大家总结了以下内容，希望大家根据这篇文章可以有所收获。
一、给定一个日期值，求出此日期所在星期的星期一和星期天的日期数据 例如给定一个日期 2010-09-01，求出它所在星期的星期一是2010-08-30，星期天是2010-09-05 Function创建如下:复制代码 代码如下: USE [MSSQL] GO SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO CREATE FUNCTION [dbo].[My_OneDay_GetWeekFirstAndEndDay](@tmpDate DATETIME) RETURNS @tmpTable TABLE(FirstDay DATETIME , EndDay DATETIME) AS BEGIN INSERT INTO @tmpTable SELECT a.FirstDay,b.EndDay FROM ( SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 0) AS FirstDAy ) a LEFT JOIN ( SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 6) AS EndDay ) b ON a.ID = b.ID RETURN End
Function测试:复制代码 代码如下: SELECT * from My_OneDay_GetWeekFirstAndEndDay('2010-09-01')
二、以上面单个日期搜索为基础，由用户输入两个参数，一个是开始日期，一个结束日期，根据这两个参数，求出在此时期段内的所有星期的星期一和星期天的日期表并排序。 例如开始日期是2011-09-01,结束日期是2011-10-06，我们就可以得到此星期表如下: WeekOrder FirstDay EndDay 1 2011-08-29 00:00:00.000 2011-09-04 00:00:00.000 2 2011-09-05 00:00:00.000 2011-09-11 00:00:00.000 3 2011-09-12 00:00:00.000 2011-09-18 00:00:00.000 4 2011-09-19 00:00:00.000 2011-09-25 00:00:00.000 5 2011-09-26 00:00:00.000 2011-10-02 00:00:00.000 6 2011-10-03 00:00:00.000 2011-10-09 00:00:00.000 Function创建如下:复制代码 代码如下: USE [MSSQL] GO SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO CREATE FUNCTION [dbo].[MY_Range_GetWeekFirstAndEndDays](@tmpDateSTART DATETIME,@tmpDateEND DATETIME) RETURNS @tmpTable TABLE(WeekOrder INT,FirstDay DATETIME , EndDay DATETIME) AS BEGIN DECLARE @tmpDate DATETIME DECLARE @index INT SET @tmpDate=@tmpDateSTART SET @index=1 WHILE @tmpDate <=@tmpDateEND BEGIN INSERT INTO @tmpTable SELECT @index,a.FirstDay,b.EndDay FROM ( SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 0) AS FirstDAy) a LEFT JOIN ( SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 6) AS EndDay) b ON a.ID = b.ID SET @tmpDate=DATEADD(DAY,7,@tmpDate) SET @index=@index+1 END RETURN End
Function测试:复制代码 代码如下: SELECT * from My_Range_GetWeekFirstAndEndDays('2011-09-01','2011-10-06')
看完上述内容，你们对SQL中怎么判断给定日期值有进一步的了解吗？如果还想了解更多知识或者相关内容，请关注亿速云行业资讯频道，感谢大家的支持。
