本文实例讲述了Android发送xml数据给服务器的方法。分享给大家供大家参考。具体如下：
一、发送xml数据：
public static void main(String[] args) throws Exception {
String xml = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><videos><video><title>中国</title></video></videos>";
String path = http://localhost:8083/videoweb/video/manage.do?method=getXML ;
byte[] entity = xml.getBytes("UTF-8");
HttpURLConnection conn = (HttpURLConnection) new URL(path).openConnection();
conn.setConnectTimeout(5000);
conn.setRequestMethod("POST");
conn.setDoOutput(true);
//指定发送的内容类型为xml
conn.setRequestProperty("Content-Type", "text/xml; charset=UTF-8");
conn.setRequestProperty("Content-Length", String.valueOf(entity.length));
OutputStream outStream = conn.getOutputStream();
outStream.write(entity);
if(conn.getResponseCode() == 200){
System.out.println("发送成功");
}else{
System.out.println("发送失败");
}
}
二、接受xml数据：
public ActionForward getXML(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response)
throws Exception {
InputStream inStream = request.getInputStream();
byte[] data = StreamTool.read(inStream);
String xml = new String(data, "UTF-8");
System.out.println(xml);
return mapping.findForward("result");
}
希望本文所述对大家的Android程序设计有所帮助。
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