本篇文章为大家展示了怎么在Python中绘制一个数码晶体管日期，内容简明扼要并且容易理解，绝对能使你眼前一亮，通过这篇文章的详细介绍希望你能有所收获。
代码：
import turtle, timedef drawLine(draw): turtle.pendown() if draw else turtle.penup() turtle.fd(40) turtle.right(90)def drawDight(dight): drawLine(True) if dight in [2, 3, 4, 5, 6, 8, 9] else drawLine(False) drawLine(True) if dight in [0, 1, 3, 4, 5, 6, 7, 8, 9] else drawLine(False) drawLine(True) if dight in [0, 2, 3, 5, 6, 8, 9] else drawLine(False) drawLine(True) if dight in [0, 2, 6, 8] else drawLine(False) turtle.left(90) drawLine(True) if dight in [0, 4, 5, 6, 8, 9] else drawLine(False) drawLine(True) if dight in [0, 2, 3, 5, 6, 7, 8, 9] else drawLine(False) drawLine(True) if dight in [0, 1, 2, 3, 4, 7, 8, 9] else drawLine(False) turtle.right(180) turtle.penup() turtle.fd(20)def drawDate(date): turtle.pencolor("red") for i in date: if i == '-': turtle.write('年', font=("微软雅黑", 32, "normal")) turtle.pencolor("green") turtle.fd(80) elif i == '=': turtle.write('月', font=("微软雅黑", 32, "normal")) turtle.pencolor("blue") turtle.fd(80) elif i == '+': turtle.write('日', font=("微软雅黑", 32, "normal")) turtle.pencolor("red") turtle.fd(80) elif i == '/': turtle.write('时', font=("微软雅黑", 32, "normal")) turtle.pencolor("green") turtle.fd(80) elif i == '*': turtle.write('分', font=("微软雅黑", 32, "normal")) turtle.pencolor("blue") turtle.fd(80) elif i == '.': turtle.write('秒', font=("微软雅黑", 32, "normal")) turtle.fd(80) else: drawDight(eval(i))if __name__ == '__main__': # turtle.setup() 我用的是pycharm,所以没有设置画布，idle下需要设置 turtle.penup() turtle.fd(-350) turtle.pensize(5) turtle.speed(1000) # 速度再大也没感觉了 drawDate(time.strftime('%Y-%m=%d+', time.localtime())) # 这里千万不要用time.gmtime())，获取的是UTC时区（0时区）的struct_time # 踩了半天坑 turtle.right(90) turtle.fd(120) turtle.right(90) turtle.fd(660) turtle.right(180) drawDate(time.strftime('%H/%M*%S.', time.localtime())) turtle.hideturtle() turtle.done()上述内容就是怎么在Python中绘制一个数码晶体管日期，你们学到知识或技能了吗？如果还想学到更多技能或者丰富自己的知识储备，欢迎关注编程网行业资讯频道。
