前言
《诈金花》又叫三张牌，是在全国广泛流传的一种民间多人纸牌游戏。比如JJ比赛中的诈金花(赢三张)，具有独特的比牌规则。游戏过程中需要考验玩家的胆略和智慧。--《百度百科》 前几天在交流群里边，有个叫【^-^】的粉丝分享了一道扑克牌诈金花的题目，要求用Python实现，题目如下：
自己写一个程序，实现发牌、比大小判断输赢。
游戏规则：
一付扑克牌，去掉大小王，每个玩家发3张牌，最后比大小，看谁赢。
有以下几种牌：
豹子：三张一样的牌，如3张6.
顺金：又称同花顺，即3张同样花色的顺子， 如红桃 5、6、7
顺子：又称拖拉机，花色不同，但是顺子，如红桃5、方片6、黑桃7，组成的顺子
对子：2张牌一样
单张：单张最大的是A
这几种牌的大小顺序为， 豹子>顺金>顺子>对子>单张
一、思路
针对这个问题，首先需要构造一副扑克牌，根据扑克牌的属性特征，进行不断的拆解，然后构造玩家用户，这里经常会用到字典和列表来存储信息，屡试不爽。
二、解决方案
针对该问题，粉丝【^-^】给出了解决方法，直接上代码如下：
# -*- coding: utf-8 -*-
import random
puke = [] # 存储扑克牌
num_list = ['2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K', 'A']
hua_list = ['梅花', '红桃', '黑桃', '方块']
sort_dic = {'2': 0, '3': 1, '4': 2, '5': 3, '6': 4, '7': 5, '8': 6, '9': 7, '10': 8, 'J': 9, 'Q': 10, 'K': 11, 'A': 12,
'对子': 15, '顺子': 30, '顺金': 60, '豹子': 100}
count_new_list = [] # 存储玩家分数和排序后排名
count_dic = {} # 存储玩家分数
# 准备52张扑克
for hua in hua_list:
for num in num_list:
a = hua + num
puke.append(a)
player_dic = {'玩家1': [], '玩家2': [], '玩家3': [], '玩家4': [], '玩家5': []}
# 随机给五个玩家发牌
# print(len(puke))
for key, value in player_dic.items():
for i in range(3):
plate = random.sample(puke, 3)
player_dic[key] = plate
for i in plate:
puke.remove(i)
print(player_dic)
# 获取玩家的牌型
def paixing(list1):
num = []
huase = []
for i in list1:
a = i[2:]
b = i[:2]
num.append(a)
huase.append(b)
return num, huase
# sort_dic = {'2': 0, '3': 1, '4': 2, '5': 3, '6': 4}
# 对数字的牌型进行排序
def sort(num):
new_num = []
sort_list2 = []
list1 = []
for i in num:
new_num.append(sort_dic[i])
new_num = sorted(new_num) # 排序后是[2, 4, 7]
for new in new_num:
sort_list2.append([k for k, v in sort_dic.items() if v == new])
for m in sort_list2:
for n in m:
list1.append(n)
return list1
# 对玩家的牌形统计分数
def count(num, huase):
a = 0
base_count = sort_dic[num[0]] + sort_dic[num[1]] + sort_dic[num[2]]
if num[0] == num[1] and num[1] == num[2]:
paixing = '豹子'
a = base_count + sort_dic[paixing]
elif (sort_dic[num[0]] + 1 == sort_dic[num[1]] and sort_dic[num[2]] - 1 == sort_dic[num[1]]) and (huase[0] == huase[
1] and huase[1] == huase[2]):
paixing = '顺金'
a = base_count + sort_dic[paixing]
elif (sort_dic[num[0]] + 1 == sort_dic[num[1]]) and (sort_dic[num[2]] - 1 == sort_dic[num[1]]) and (
huase[0] != huase[
1] or huase[1] != huase[2]):
paixing = '顺子'
a = base_count + sort_dic[paixing]
elif (num[0] == num[1] and num[1] != num[2]) or (num[1] == num[2] and num[0] != num[1]) or (
num[0] == num[2] and num[1] != num[0]):
paixing = '对子'
a = base_count + sort_dic[paixing]
else:
a = base_count
return a
# 对存储玩家分数的字典进行排序
def compare(count_dic):
d = list(zip(count_dic.values(), count_dic.keys()))
return sorted(d, reverse=True)
for key, value in player_dic.items():
num, huase = paixing(value)
num = sort(num)
count1 = count(num, huase)
count_dic[key] = count1
print(key + "的牌为：" + str(value))
count_new_list = compare(count_dic)
# print(count_new_list)
print('最终排名：' + "\t" + count_new_list[0][1] + "第一名" + "\t" + count_new_list[1][1] + "第二名" + "\t" + count_new_list[2][
1] + "第三名" + "\t" + count_new_list[3][1] + "第四名" + "\t" + count_new_list[4][1] + "第五名")代码看上去确实挺多的，超过了100行，需要花点时间去读，不过涉及的知识点并不复杂，基本上有点Python基础，也可以理解。代码运行之后，可以看到效果如下：
不过后来我在读取这份代码的时候，发现中间有个地方写的着实有些冗余，稍微修改下，代码方面简洁一些，一些函数和变量命名加了一些对应的现实意义的单词，可读性强了一丢丢，代码如下：
# -*- coding: utf-8 -*-
import random
puke = [] # 存储扑克牌
num_list = ['2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K', 'A']
hua_list = ['梅花', '红桃', '黑桃', '方块']
sort_dic = {'2': 0, '3': 1, '4': 2, '5': 3, '6': 4, '7': 5, '8': 6, '9': 7, '10': 8, 'J': 9, 'Q': 10, 'K': 11, 'A': 12,
'对子': 15, '顺子': 30, '顺金': 60, '豹子': 100}
count_new_list = [] # 存储玩家分数和排序后排名
count_dic = {} # 存储玩家分数
# 准备52张扑克
for hua in hua_list:
for num in num_list:
a = hua + num
puke.append(a)
player_dic = {'玩家1': [], '玩家2': [], '玩家3': [], '玩家4': [], '玩家5': []}
# 随机给五个玩家发牌
print(len(puke))
for key, value in player_dic.items():
for i in range(3):
plate = random.sample(puke, 3)
player_dic[key] = plate
for i in plate:
puke.remove(i)
print(player_dic)
# 获取玩家的牌型
def paixing(list1):
num = []
huase = []
for data in list1:
huase_type = data[:2]
pai_number = data[2:]
num.append(pai_number)
huase.append(huase_type)
return num, huase
# 对玩家的牌形统计分数
def get_score(num, huase):
base_count = sort_dic[num[0]] + sort_dic[num[1]] + sort_dic[num[2]]
if num[0] == num[1] and num[1] == num[2]:
paixing = '豹子'
score = base_count + sort_dic[paixing]
elif (sort_dic[num[0]] + 1 == sort_dic[num[1]] and sort_dic[num[2]] - 1 == sort_dic[num[1]]) and (huase[0] == huase[
1] and huase[1] == huase[2]):
paixing = '顺金'
score = base_count + sort_dic[paixing]
elif (sort_dic[num[0]] + 1 == sort_dic[num[1]]) and (sort_dic[num[2]] - 1 == sort_dic[num[1]]) and (
huase[0] != huase[
1] or huase[1] != huase[2]):
paixing = '顺子'
score = base_count + sort_dic[paixing]
elif (num[0] == num[1] and num[1] != num[2]) or (num[1] == num[2] and num[0] != num[1]) or (
num[0] == num[2] and num[1] != num[0]):
paixing = '对子'
score = base_count + sort_dic[paixing]
else:
score = base_count
return score
if __name__ == '__main__':
for key, value in player_dic.items():
num, huase = paixing(value)
# 对数字的牌型进行排序
num = sorted(num)
score = get_score(num, huase)
count_dic[key] = score
print(key + "的牌为：" + str(value))
# 对存储玩家分数的字典进行排序
count_new_list = sorted(zip(count_dic.values(), count_dic.keys()), reverse=True)
print("最终排名：")
for i in range(len(count_new_list)):
print(count_new_list[i][1] + '\t', end='')三、总结
我是Python进阶者。本文实际生活中的诈金花游戏，基于Python编程，使用Python基础知识中的列表、字典、函数等，实现了在线诈金花的过程。
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