Prim算法随机生成后的迷宫数列矩阵如下图:
15x15:
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 s 0 1 0 1 0 1 1 1 1 1 0 1 0
0 1 0 1 0 1 0 0 0 1 0 0 0 1 0
0 1 1 1 1 1 1 1 1 1 1 1 0 1 0
0 1 0 0 0 1 0 0 0 1 0 0 0 1 0
0 1 0 1 1 1 0 1 1 1 0 1 0 1 0
0 0 0 0 0 0 0 0 0 1 0 1 0 1 0
0 1 1 1 1 1 1 1 1 1 1 1 1 1 0
0 1 0 1 0 0 0 1 0 0 0 1 0 0 0
0 1 0 1 0 1 1 1 0 1 1 1 1 1 0
0 1 0 1 0 0 0 1 0 0 0 1 0 1 0
0 1 0 1 0 1 1 1 1 1 0 1 0 1 0
0 0 0 1 0 0 0 1 0 0 0 0 0 1 0
0 1 1 1 0 1 1 1 1 1 1 e 0 1 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
27x27:
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 s 1 1 0 1 0 1 1 1 1 1 1 1 1 1 1 1 0 1 0 1 1 1 1 1 0
0 0 0 1 0 1 0 0 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 1 0 0 0
0 1 1 1 0 1 0 1 1 1 0 1 0 1 1 1 1 1 0 1 0 1 1 1 1 1 0
0 0 0 1 0 1 0 0 0 1 0 1 0 1 0 0 0 0 0 1 0 0 0 1 0 0 0
0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 1 0 1 0 1 1 1 0
0 1 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 1 0 1 0 1 0 0 0
0 1 0 1 0 1 0 1 0 1 1 1 0 1 1 1 0 1 0 1 0 1 0 1 1 1 0
0 0 0 1 0 1 0 1 0 0 0 1 0 1 0 0 0 1 0 1 0 1 0 1 0 0 0
0 1 0 1 1 1 0 1 0 1 0 1 1 1 0 1 0 1 1 1 0 1 1 1 1 1 0
0 1 0 0 0 1 0 1 0 1 0 1 0 0 0 1 0 1 0 0 0 1 0 0 0 0 0
0 1 0 1 1 1 1 1 1 1 0 1 0 1 0 1 0 1 1 1 1 1 1 1 0 1 0
0 1 0 0 0 0 0 1 0 0 0 1 0 1 0 1 0 1 0 0 0 0 0 0 0 1 0
0 1 1 1 1 1 1 1 0 1 0 1 1 1 0 1 1 1 1 1 0 1 0 1 0 1 0
0 0 0 0 0 0 0 1 0 1 0 0 0 1 0 1 0 0 0 0 0 1 0 1 0 1 0
0 1 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0
0 0 0 1 0 0 0 1 0 1 0 1 0 1 0 1 0 0 0 0 0 1 0 1 0 1 0
0 1 1 1 1 1 1 1 0 1 0 1 0 1 0 1 1 1 1 1 0 1 0 1 0 1 0
0 0 0 1 0 1 0 1 0 1 0 0 0 0 0 1 0 1 0 1 0 1 0 0 0 0 0
0 1 1 1 0 1 0 1 0 1 0 1 1 1 1 1 0 1 0 1 0 1 1 1 1 1 0
0 0 0 1 0 0 0 0 0 1 0 0 0 1 0 1 0 0 0 0 0 1 0 1 0 1 0
0 1 1 1 1 1 1 1 0 1 0 1 1 1 0 1 1 1 1 1 0 1 0 1 0 1 0
0 1 0 1 0 1 0 1 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 1 0 0 0
0 1 0 1 0 1 0 1 0 1 1 1 1 1 0 1 1 1 1 1 0 1 0 1 1 1 0
0 1 0 0 0 0 0 1 0 0 0 1 0 1 0 1 0 1 0 0 0 1 0 0 0 0 0
0 1 1 1 e 1 0 1 0 1 1 1 0 1 0 1 0 1 1 1 1 1 1 1 1 1 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
实现该效果的代码如下:
import random as rd
nearmaybe=[
[-2,0],
[2,0],
[0,-2],
[0,2]
]
def createMaze(row,col):
maze=[[0 for i in range(col)] for i in range(row)]
check=[]
firstrow=rd.randrange(1,row-2,2)
firstcol=rd.randrange(1,col-2,2)
maze[firstrow][firstcol]=1
check.append([firstrow,firstcol])
while len(check):
c=rd.choice(check)
nears=[]
conditions=[]
for maybe in nearmaybe:
conditions.append([c[0]+maybe[0],c[1]+maybe[1]])
for condition in conditions:
if condition[0]>=1 and condition[0]<=row-2 \
and condition[1]>=1 and condition[1]<=col-2:
nears.append([condition[0],condition[1]])
for n in nears.copy():
if maze[n[0]][n[1]]:
nears.remove(n)
for block in nears:
if block[0]==c[0]:
if block[1]<c[1]:
maze[block[0]][c[1]-1]=1
maze[block[0]][block[1]]=1
check.append([block[0],block[1]])
else:
maze[block[0]][block[1]-1]=1
maze[block[0]][block[1]]=1
check.append([block[0],block[1]])
else:
if block[0]<c[0]:
maze[c[0]-1][block[1]]=1
maze[block[0]][block[1]]=1
check.append([block[0],block[1]])
else:
maze[block[0]-1][block[1]]=1
maze[block[0]][block[1]]=1
check.append([block[0],block[1]])
if not len(nears):
check.remove(c)
maze[1][1]="s"
while True:
c=rd.randint(1,col-2)
if maze[row-2][c]:
maze[row-2][c]="e"
break
return maze
调用该函数的方法:
maze=createMaze(27,27)
for l in maze:
for s in l:
print(s,end=" ")
print()
CreateMaze传入的两个参数必须都是单数,否则程序可能会无法运行!
下面的for循环遍历就是将生成的迷宫矩阵打印出来
S表示出发点
1表示路
0表示墙
E表示终点
生成迷宫矩阵后,就可以将其引用到游戏中去啦!
到此这篇关于Python利用Prim算法生成迷宫的文章就介绍到这了,更多相关Python Prim生成迷宫内容请搜索编程网以前的文章或继续浏览下面的相关文章希望大家以后多多支持编程网!