用到了wrapper,整理资料记录一下,以备后续复习。
一、条件构造器关系介绍
条件构造器关系介绍 :
上图绿色框为抽象类abstract
蓝色框为正常class类,可new对象
黄色箭头指向为父子类关系,箭头指向为父类
wapper介绍 :
Wrapper : 条件构造抽象类,最顶端父类
AbstractWrapper : 用于查询条件封装,生成 sql 的 where 条件
QueryWrapper : Entity 对象封装操作类,不是用lambda语法
UpdateWrapper : Update 条件封装,用于Entity对象更新操作
AbstractLambdaWrapper : Lambda 语法使用 Wrapper统一处理解析 lambda 获取 column。
LambdaQueryWrapper :看名称也能明白就是用于Lambda语法使用的查询Wrapper
LambdaUpdateWrapper : Lambda 更新封装Wrapper
二、项目实例
1、根据主键或者简单的查询条件进行查询
@Test
public void selectById() {
User user = userMapper.selectById(1094592041087729666L);
System.out.println(user);
}
@Test
public void selectByWrapperOne() {
QueryWrapper<User> wrapper = new QueryWrapper();
wrapper.like("name", "雨").lt("age", 40);
List<User> users = userMapper.selectList(wrapper);
users.forEach(System.out::println);
}
/**
* 名字包含雨
* 年龄大于20小于40
* 邮箱不能为空
* WHERE name LIKE '%雨%' AND age BETWEEN 20 AND 40 AND email IS NOT NULL
public void selectByWrapperTwo() {
QueryWrapper<User> wrapper = Wrappers.query();
wrapper.like("name", "雨").between("age", 20, 40).isNotNull("email");
* 名字为王性
* 或者年龄大于等于25
* 按照年龄降序排序,年龄相同按照id升序排序
* WHERE name LIKE '王%' OR age >= 25 ORDER BY age DESC , id ASC
public void selectByWrapperThree() {
wrapper.likeRight("name", "王").or()
.ge("age", 25).orderByDesc("age").orderByAsc("id");
* 查询创建时间为2019年2月14
* 并且上级领导姓王
* WHERE date_format(create_time,'%Y-%m-%d') = '2019-02-14' AND manager_id IN (select id from user where name like '王%')
public void selectByWrapperFour() {
wrapper.apply("date_format(create_time,'%Y-%m-%d') = {0}", "2019-02-14")
.inSql("manager_id", "select id from user where name like '王%'");
* 查询王姓
* 并且年龄小于40或者邮箱不为空
* WHERE name LIKE '王%' AND ( age < 40 OR email IS NOT NULL )
public void selectByWrapperFive() {
wrapper.likeRight("name", "王").and(qw -> qw.lt("age", 40).or().isNotNull("email"));
* 并且年龄大于20 、年龄小于40、邮箱不能为空
* WHERE name LIKE ? OR ( age BETWEEN ? AND ? AND email IS NOT NULL )
public void selectByWrapperSix() {
wrapper.likeRight("name", "王").or(
qw -> qw.between("age", 20, 40).isNotNull("email")
);
* (年龄小于40或者邮箱不为空) 并且名字姓王
* WHERE ( age < 40 OR email IS NOT NULL ) AND name LIKE '王%'
public void selectByWrapperSeven() {
wrapper.nested(qw -> qw.lt("age", 40).or().isNotNull("email"))
.likeRight("name", "王");
* 查询年龄为30、31、32
* WHERE age IN (?,?,?)
public void selectByWrapperEight() {
wrapper.in("age", Arrays.asList(30, 31, 32));
* 查询一条数据
* limit 1
public void selectByWrapperNine() {
wrapper.in("age", Arrays.asList(30, 31, 32)).last("limit 1");
三、具体使用操作
注意:以下条件构造器的方法入参中的 column
均表示数据库字段
1、ge、gt、le、lt、isNull、isNotNull
@Test
public void testDelete() {
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
queryWrapper
.isNull("name")
.ge("age", 12)
.isNotNull("email");
int result = userMapper.delete(queryWrapper);
System.out.println("delete return count = " + result);
}
SQL:UPDATE user SET deleted=1 WHERE deleted=0 AND name IS NULL AND age >= ? AND email IS NOT NULL
2、eq、ne
注意:seletOne返回的是一条实体记录,当出现多条时会报错
@Test
public void testSelectOne() {
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
queryWrapper.eq("name", "Tom");
User user = userMapper.selectOne(queryWrapper);
System.out.println(user);
}
3、between、notBetween
包含大小边界
@Test
public void testSelectCount() {
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
queryWrapper.between("age", 20, 30);
Integer count = userMapper.selectCount(queryWrapper);
System.out.println(count);
}
SELECT COUNT(1) FROM user WHERE deleted=0 AND age BETWEEN ? AND ?
4、allEq
@Test
public void testSelectList() {
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
Map<String, Object> map = new HashMap<>();
map.put("id", 2);
map.put("name", "Jack");
map.put("age", 20);9
queryWrapper.allEq(map);
List<User> users = userMapper.selectList(queryWrapper);
users.forEach(System.out::println);
}
SELECT id,name,age,email,create_time,update_time,deleted,version FROM user WHERE deleted=0 AND name = ? AND id = ? AND age = ?
5、like、notLike、likeLeft、likeRight
selectMaps返回Map集合列表
@Test
public void testSelectMaps() {
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
queryWrapper
.notLike("name", "e")
.likeRight("email", "t");
List<Map<String, Object>> maps = userMapper.selectMaps(queryWrapper);//返回值是Map列表
maps.forEach(System.out::println);
}
SELECT id,name,age,email,create_time,update_time,deleted,version FROM user WHERE deleted=0 AND name NOT LIKE ? AND email LIKE ?
6、in、notIn、inSql、notinSql、exists、notExists
in、notIn:
notIn("age",{1,2,3})--->age not in (1,2,3)
notIn("age", 1, 2, 3)--->age not in (1,2,3)
inSql、notinSql:可以实现子查询
例: inSql("age", "1,2,3,4,5,6")--->age in (1,2,3,4,5,6)
例: inSql("id", "select id from table where id < 3")--->id in (select id from table where id < 3)
SELECT id,name,age,email,create_time,update_time,deleted,version FROM user WHERE deleted=0 AND id IN (select id from user where id < 3)
7、or、and
注意:这里使用的是 UpdateWrapper 不调用or则默认为使用 and 连
@Test
public void testSelectObjs() {
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
//queryWrapper.in("id", 1, 2, 3);
queryWrapper.inSql("id", "select id from user where id < 3");
List<Object> objects = userMapper.selectObjs(queryWrapper);//返回值是Object列表
objects.forEach(System.out::println);
}
UPDATE user SET name=?, age=?, update_time=? WHERE deleted=0 AND name LIKE ? OR age BETWEEN ? AND ?
8、嵌套or、嵌套and
这里使用了lambda表达式,or中的表达式最后翻译成sql时会被加上圆括号
@Test
public void testUpdate1() {
//修改值
User user = new User();
user.setAge(99);
user.setName("Andy");
//修改条件
UpdateWrapper<User> userUpdateWrapper = new UpdateWrapper<>();
userUpdateWrapper
.like("name", "h")
.or()
.between("age", 20, 30);
int result = userMapper.update(user, userUpdateWrapper);
System.out.println(result);
}
UPDATE user SET name=?, age=?, update_time=?
WHERE deleted=0 AND name LIKE ?
OR ( name = ? AND age <> ? )
9、orderBy、orderByDesc、orderByAsc
@Test
public void testUpdate2() {
//修改值
User user = new User();
user.setAge(99);
user.setName("Andy");
//修改条件
UpdateWrapper<User> userUpdateWrapper = new UpdateWrapper<>();
userUpdateWrapper
.like("name", "h")
.or(i -> i.eq("name", "李白").ne("age", 20));
int result = userMapper.update(user, userUpdateWrapper);
System.out.println(result);
}
SELECT id,name,age,email,create_time,update_time,deleted,version
FROM user WHERE deleted=0 ORDER BY id DESC
10、last
直接拼接到 sql 的最后
注意:只能调用一次,多次调用以最后一次为准 有sql注入的风险,请谨慎使用
@Test
public void testSelectListLast() {
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
queryWrapper.last("limit 1");
List<User> users = userMapper.selectList(queryWrapper);
users.forEach(System.out::println);
}
SELECT id,name,age,email,create_time,update_time,deleted,version
FROM user WHERE deleted=0 limit 1
11、指定要查询的列
@Test
public void testSelectListColumn() {
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
queryWrapper.select("id", "name", "age");
List<User> users = userMapper.selectList(queryWrapper);
users.forEach(System.out::println);
}
SELECT id,name,age FROM user WHERE deleted=0
12、set、setSql
最终的sql会合并 user.setAge(),以及 userUpdateWrapper.set() 和 setSql() 中 的字段
@Test
public void testUpdateSet() {
//修改值
User user = new User();
user.setAge(99);
//修改条件
UpdateWrapper<User> userUpdateWrapper = new UpdateWrapper<>();
userUpdateWrapper
.like("name", "h")
.set("name", "老李头")//除了可以查询还可以使用set设置修改的字段
.setSql(" email = '123@qq.com'");//可以有子查询
int result = userMapper.update(user, userUpdateWrapper);
}
UPDATE user SET age=?, update_time=?, name=?, email = '123@qq.com' WHERE deleted=0 AND name LIKE ?
参考文档
1、https://blog.csdn.net/m0_37034294/article/details/82917234
2、https://blog.csdn.net/kepengs/article/details/112345870
3、https://blog.csdn.net/weixin_39615889/article/details/107086931
4、https://blog.csdn.net/weixin_38111957/article/details/91447509
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