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题目一
解法
class Solution { public String reverseOnlyLetters(String s) { char[] chars = s.toCharArray(); int left = 0; int right = chars.length-1; while(left<=right){ char tmp = 0; if(chars[left]>='a'&&chars[left]<='z'||(chars[left]>='A'&&chars[left]<='Z')){ tmp = chars[left]; }else { left++; continue; } if(chars[right]>='a'&&chars[right]<='z'||(chars[right]>='A'&&chars[right]<='Z')){ chars[left] = chars[right]; chars[right] = tmp; }else { right--; continue; } left++; right--; } return new String(chars); }}题目二
解法
class Solution { public TreeNode increasingBST(TreeNode root) { ArrayList<Integer> list = new ArrayList<Integer>(); method(root,list); TreeNode ans = new TreeNode(-1); TreeNode cur = ans; for(int i:list){ TreeNode node = new TreeNode(i); cur.right = node; cur = cur.right; } return ans.right; } public void method(TreeNode root,List<Integer> list){ if(root==null) return; method(root.left,list); list.add(root.val); method(root.right,list); }}题目三
解法
class Solution { public int[] sortArrayByParity(int[] nums) { int[] ans = new int[nums.length]; int left = 0; int right = nums.length-1; for(int i : nums){ if(i%2==0){ ans[left] = i; left++; }else{ ans[right] = i; right--; } } return ans; }} class Solution { public int[] sortArrayByParity(int[] nums) { int left = 0; int right = nums.length-1; while(left<=right){ if(nums[left]%2==0){ left++; continue; } if(nums[right]%2!=0){ right--; continue; } if(nums[left]%2!=0&&nums[right]%2==0){ int tmp = nums[left]; nums[left] = nums[right]; nums[right] = tmp; } } return nums; }}题目四
解法
class Solution { public boolean backspaceCompare(String s, String t) { if(method(s).equals(method(t))) return true; return false; } public static String method(String s){ int slow = 0; char[] chars = s.toCharArray(); for (int i = 0; i < chars.length; i++) { if(chars[i]=='#'){ chars[i] = 0; slow = i; while (true){ if(slow-1<0) break; if (chars[slow-1]!=0){ chars[slow-1] = 0; break; } slow--; } } } StringBuilder sb = new StringBuilder(); for(char i : chars){ if(i!=0) sb.append(i); } return sb.toString(); }}读到这里，这篇“Java字符串，数组及二叉搜索树实例分析”文章已经介绍完毕，想要掌握这篇文章的知识点还需要大家自己动手实践使用过才能领会，如果想了解更多相关内容的文章，欢迎关注编程网行业资讯频道。
