php小编鱼仔发现，使用ozzo验证库可以轻松实现数据验证，但有时候可能会遇到需要调用嵌入结构的验证方法的情况。然而，ozzo验证库的设计原则是避免调用嵌入结构的验证方法，以确保代码的简洁性和可读性。这是因为嵌入结构的验证方法可能导致验证逻辑的复杂化，并且会增加代码的维护难度。因此，在使用ozzo验证库时，我们应该遵循这一原则，选择适合的验证方式，以保持代码的清晰和易于维护。
问题内容
我正在使用 "github.com/go-ozzo/ozzo-validation/v4"。
这些是我的结构：
type mystruct struct {
uuid string `json:"uuid"`
firstuuid string `json:"first_uuid"`
seconduuid string `json:"second_uuid"`
thirduuid string `json:"third_uuid"`
phonenumber string `json:"phone_number"`
email string `json:"email"`
skypeid string `json:"skype_id"`
}
type myotherstruct struct {
mystruct
city string `json:"city"`
comment string `json:"comment"`
personnelid string `json:"personnel_id"`
firstdate string `json:"first_date"`
seconddate string `json:"second_date"`
firstboolean bool `json:"first_boolean"`
secondboolean bool `json:"second_boolean"`
}这些是验证方法：
func (m mystruct) validate() error {
fmt.println("calling mystruct validator")
err := validation.validatestruct(
validation.field(&uui.uuid, is.uuid),
validation.field(&uui.firstuuid, validation.required, is.uuid),
validation.field(&uui.seconduuid, validation.required, is.uuid),
validation.field(&uui.thirduuid, validation.required, is.uuid),
validation.field(&uui.email, validation.required, is.email),
validation.field(&uui.phonenumber, validation.required, validation.match(mobileregexp)),
validation.field(&uui.skypeid, validation.required),
)
return err
}
func (m myotherstruct) validate() error {
fmt.println("calling myotherstruct validator")
err := validation.validatestruct(
validation.field(&uui.personnelid, validation.match(personnelidregexp)),
validation.field(&uui.city, validation.required),
validation.field(&uui.comment),
validation.field(&uui.firstdate, validation.date(time.dateonly)),
validation.field(&uui.seconddate, validation.date(time.dateonly)),
)
return err
}这是我发送的请求：
{
"uuid": "1e57ef49-352f-4545-a43a-b51cad6c5a0a",
"phone_number": "09124567891",
"email": "[email protected]",
"skype_id": "some_skype_id",
"city": "a city",
"personnel_id": "",
"comment": "no comment for now!",
"first_date": "",
"second_date": "",
"first_uuid": "94038913-2bdb-4dde-99fb-640a24e1c003",
"second_uuid": "7fa0e242-841b-4de0-a3ce-e2b54ecd1bca",
"third_uuid": "35ab6711-852e-42c8-aab3-dfb901a845f5",
"first_boolean": true,
"second_boolean": false
}我希望针对此问题调用 func (m mystruct) validate()，但我没有收到日志 calling myotherstruct validator。
解决方法
问题中的源代码与ozzo 验证 v4 返回在结构中找不到字段 #0。除此之外，您应该将以下代码添加到 (myotherstruct).validate：
validation.field(&m.mystruct),
尝试这个演示（https://www.php.cn/link/9f29450d2eb58feb555078bdefe28aa5 ）：
package main
import (
"fmt"
validation "github.com/go-ozzo/ozzo-validation/v4"
"github.com/go-ozzo/ozzo-validation/v4/is"
)
type MyStruct struct {
UUID string `json:"uuid"`
Email string `json:"email"`
}
func (m MyStruct) Validate() error {
fmt.Println("calling MyStruct validator")
err := validation.ValidateStruct(
&m,
validation.Field(&m.UUID, is.UUID),
validation.Field(&m.Email, validation.Required, is.Email),
)
return err
}
type MyOtherStruct struct {
MyStruct
City string `json:"city"`
}
func (m MyOtherStruct) Validate() error {
fmt.Println("calling MyOtherStruct validator")
err := validation.ValidateStruct(
&m,
validation.Field(&m.City, validation.Required),
// The following line is necessary to make (MyStruct).Validate being called.
validation.Field(&m.MyStruct),
)
return err
}
func main() {
data := MyOtherStruct{}
fmt.Printf("validation error: %v\n", data.Validate())
}
请注意，如果您调用 (mystruct).validate，则 (myotherstruct).validate 不会被调用，因为前者对 myotherstruct 一无所知。
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