这篇文章主要介绍R语言逻辑回归的示例分析，文中介绍的非常详细，具有一定的参考价值，感兴趣的小伙伴们一定要看完！
逻辑回归
> ###############逻辑回归> setwd("/Users/yaozhilin/Downloads/R_edu/data")> accepts<-read.csv("accepts.csv")> names(accepts) [1] "application_id" "account_number" "bad_ind" "vehicle_year" "vehicle_make" [6] "bankruptcy_ind" "tot_derog" "tot_tr" "age_oldest_tr" "tot_open_tr" [11] "tot_rev_tr" "tot_rev_debt" "tot_rev_line" "rev_util" "fico_score" [16] "purch_price" "msrp" "down_pyt" "loan_term" "loan_amt" [21] "ltv" "tot_income" "veh_mileage" "used_ind" > accepts<-accepts[complete.cases(accepts),]> select<-sample(1:nrow(accepts),length(accepts$application_id)*0.7)> train<-accepts[select,]###70%用于建模> test<-accepts[-select,]###30%用于检测> attach(train)> ###用glm(y~x,family=binomial(link="logit"))> gl<-glm(bad_ind~fico_score,family=binomial(link = "logit"))> summary(gl)Call:glm(formula = bad_ind ~ fico_score, family = binomial(link = "logit"))Deviance Residuals: Min 1Q Median 3Q Max -2.0794 -0.6790 -0.4937 -0.3073 2.6028 Coefficients: Estimate Std. Error z value Pr(>|z|) (Intercept) 9.049667 0.629120 14.38 <2e-16 ***fico_score -0.015407 0.000938 -16.43 <2e-16 ***---Signif. codes: 0 ‘***' 0.001 ‘**' 0.01 ‘*' 0.05 ‘.' 0.1 ‘ ' 1(Dispersion parameter for binomial family taken to be 1) Null deviance: 2989.2 on 3046 degrees of freedomResidual deviance: 2665.9 on 3045 degrees of freedomAIC: 2669.9Number of Fisher Scoring iterations: 5多元逻辑回归
> ###多元逻辑回归> gls<-glm(bad_ind~fico_score+bankruptcy_ind+age_oldest_tr++ tot_derog+rev_util+veh_mileage,family = binomial(link = "logit"))> summary(gls)Call:glm(formula = bad_ind ~ fico_score + bankruptcy_ind + age_oldest_tr + tot_derog + rev_util + veh_mileage, family = binomial(link = "logit"))Deviance Residuals: Min 1Q Median 3Q Max -2.2646 -0.6743 -0.4647 -0.2630 2.8177 Coefficients: Estimate Std. Error z value Pr(>|z|) (Intercept) 8.205e+00 7.433e-01 11.039 < 2e-16 ***fico_score -1.338e-02 1.092e-03 -12.260 < 2e-16 ***bankruptcy_indY -3.771e-01 1.855e-01 -2.033 0.0421 * age_oldest_tr -4.458e-03 6.375e-04 -6.994 2.68e-12 ***tot_derog 3.012e-02 1.552e-02 1.941 0.0523 . rev_util 3.763e-04 5.252e-04 0.717 0.4737 veh_mileage 2.466e-06 1.381e-06 1.786 0.0741 . ---Signif. codes: 0 ‘***' 0.001 ‘**' 0.01 ‘*' 0.05 ‘.' 0.1 ‘ ' 1(Dispersion parameter for binomial family taken to be 1) Null deviance: 2989.2 on 3046 degrees of freedomResidual deviance: 2601.4 on 3040 degrees of freedomAIC: 2615.4Number of Fisher Scoring iterations: 5> glss<-step(gls,direction = "both")Start: AIC=2615.35bad_ind ~ fico_score + bankruptcy_ind + age_oldest_tr + tot_derog + rev_util + veh_mileage Df Deviance AIC- rev_util 1 2601.9 2613.9<none> 2601.3 2615.3- veh_mileage 1 2604.4 2616.4- tot_derog 1 2605.1 2617.1- bankruptcy_ind 1 2605.7 2617.7- age_oldest_tr 1 2655.9 2667.9- fico_score 1 2763.8 2775.8Step: AIC=2613.88bad_ind ~ fico_score + bankruptcy_ind + age_oldest_tr + tot_derog + veh_mileage Df Deviance AIC<none> 2601.9 2613.9- veh_mileage 1 2604.9 2614.9+ rev_util 1 2601.3 2615.3- tot_derog 1 2605.7 2615.7- bankruptcy_ind 1 2606.1 2616.1- age_oldest_tr 1 2656.9 2666.9- fico_score 1 2773.2 2783.2> #出来的数据是logit，我们需要转换> train$pre<-predict(glss,train)> #出来的数据是logit，我们需要转换> train$pre<-predict(glss,train)> summary(train$pre) Min. 1st Qu. Median Mean 3rd Qu. Max. -4.868 -2.421 -1.671 -1.713 -1.011 2.497 > train$pre_p<-1/(1+exp(-1*train$pre))> summary(train$pre_p) Min. 1st Qu. Median Mean 3rd Qu. Max. 0.00763 0.08157 0.15823 0.19298 0.26677 0.92395 #逻辑回归不需要检测扰动项，但需要检测共线性 > library(car) > vif(glss) > fico_score bankruptcy_ind age_oldest_tr tot_derog veh_mileage >1.271283 1.144846 1.075603 1.423850 1.003616以上是“R语言逻辑回归的示例分析”这篇文章的所有内容，感谢各位的阅读！希望分享的内容对大家有帮助，更多相关知识，欢迎关注编程网行业资讯频道！
