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使用SUM函数,加上GROUP BY人员ID就可以实现了:
SELECT SUM(PZ+CPJS+BZ+GC+SB+TG+MJ+CL+CCLW+GJ+ZL+CBZZ) as count,
SUM(PZ) as PZ,SUM(CPJS) as CPJS,SUM(BZ) as BZ,SUM(GC) as GC,SUM(SB) as SB,SUM(TG) as TG,SUM(MJ) as MJ,SUM(CL) as CL,SUM(CCLW) as CCLW,SUM(GJ) as GJ,SUM(ZL) as ZL,SUM(CBZZ) as CBZZ,SUM(YHID) as YHID,SUM(DJRMC) as DJRMC FROM tableName WHERE YHID='$ID' AND NF='$NF' GROUP BY YHID;
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