sql server 递归查询树型结构某节点的所有上级节点，并且把这些所有上级节点多行拼接为一行，即合并列数据
with eps_root(pk_eps, pk_parent, eps_code, eps_name) as
(
SELECT
pk_eps, pk_parent, eps_code, eps_name
FROM pm_eps
where enablestate = 2
and pk_eps = '1001A11000000003P62E'
union all
SELECT
e.pk_eps, e.pk_parent, e.eps_code, e.eps_name
FROM pm_eps e
inner join eps_root r on e.pk_eps = r.pk_parent
where e.enablestate = 2
)
select distinct
eps_code = stuff((select '/' + convert(nvarchar(500), eps_code) from (select distinct eps_code from eps_root) r1 for xml path('')), 1, 1, ''),
--此次需要使用eps_code排序，不然中文的会错乱顺序
eps_name = stuff((select '/' + eps_name from (select top 99.99 PERCENT eps_name from eps_root order by eps_code) r2 for xml path('')), 1, 1, '')
from eps_root
执行sql，如下图效果：
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